VectorDraw Developer Framework
问:如何删除Layer1的所有实体/span>
答:在下面的示例中,我们从所有布局和块中删除所有引用Layer1的实体,因此,如果一个块包含来自多个图层的实体,则将删除引用第1层的实体。
//returns the handle of the layer of the passed entity function GetEntityLayerHandle(vdrawobj, document, entity) { var ret = entity.Layer; if (!ret) {//if not exist asume that it belongs to Layer '0' ret = vdrawobj.FindLayer("0"); if (!ret) ret = 'h_'; else ret = "h_" + ret.HandleId.toString(); } return ret; } //set the Deleted property of the entities that belongs to layer with passed layerHandle, to true //Note: Entities with Deleted == true are not draw and they are not saved function deleteEntitiesOnLayer(vdrawobj,document, handlecollection, layerHandle) { for (var i = 0; i < handlecollection.Items.length; i++) { var ent = vdrawobj.GetDictItem(handlecollection, handlecollection.Items[i]); if (!ent) continue; var layerentity = GetEntityLayerHandle(vdrawobj,document,ent); if (layerentity == layerHandle) ent.Deleted = true; } } function test() { //Mark all the entities, of all layouts and all blocks, that have property Layer == Layer 1 handle as Deleted = true var layer1 = vdcanvas.FindLayer('Layer1'); var layerHandle = "h_" + layer1.HandleId.toString(); var vddoc = vdcanvas.GetDocument(); deleteEntitiesOnLayer(vdcanvas, vddoc, vddoc.Model.Entities, layerHandle); if (vddoc.LayOuts) { for (var i = 0; i < vddoc.LayOuts.Items.length; i++) { deleteEntitiesOnLayer(vdcanvas, vddoc, vddoc.LayOuts.Items[i].Entities, layerHandle); } } if (vddoc.Blocks) { for (var i = 0; i < vddoc.Blocks.Items.length; i++) { var block = vdcanvas.GetDictItem(vddoc.Blocks, vddoc.Blocks.Items[i]); if (!block) continue; deleteEntitiesOnLayer(vdcanvas, vddoc, block.Entities, layerHandle); } } vdcanvas.UpdateLayout(); setTimeout(vdcanvas.redraw); }
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