java 计算器怎么实现连续计算_java swing实现简单的计算器可加减乘除连续计算

java swing实现简单的计算器可加减乘除连续计算

java swing实现简单的计算器可加减乘除连续计算

1，首先展示效果图

2.核心=代码如下：

public void actionPerformed(ActionEvent e) {

text.setText(text.getText()+equ.getText());

if(text.getText().contains(“+”)){//做加法运算

StringTokenizer st1 = new StringTokenizer(text.getText(),”+”);

double d1,d2 = 0;

d1 = Double.parseDouble(st1.nextToken());

while(st1.hasMoreTokens()){

StringTokenizer st2 = new StringTokenizer(st1.nextToken(),”=”);

d2 = Double.parseDouble(st2.nextToken());

}

text.setText(text.getText()+” “+(d1+d2));

}else if(text.getText().contains(“-“)){//做减法运算

StringTokenizer st1 = new StringTokenizer(text.getText(),”-“);

double d1,d2 = 0;

d1 = Double.parseDouble(st1.nextToken());

while(st1.hasMoreTokens()){

StringTokenizer st2 = new StringTokenizer(st1.nextToken(),”=”);

d2 = Double.parseDouble(st2.nextToken());

}

text.setText(text.getText()+” “+(d1-d2));

}else if(text.getText().contains(“*”)){//做乘法运算

StringTokenizer st1 = new StringTokenizer(text.getText(),”*”);

double d1,d2 = 0;

d1 = Double.parseDouble(st1.nextToken());

while(st1.hasMoreTokens()){

StringTokenizer st2 = new StringTokenizer(st1.nextToken(),”=”);

d2 = Double.parseDouble(st2.nextToken());

}

text.setText(text.getText()+” “+(d1*d2));

}else if(text.getText().contains(“/”)){//做除法运算

StringTokenizer st1 = new StringTokenizer(text.getText(),”/”);

double d1,d2 = 0;

d1 = Double.parseDouble(st1.nextToken());

while(st1.hasMoreTokens()){

StringTokenizer st2 = new StringTokenizer(st1.nextToken(),”=”);

d2 = Double.parseDouble(st2.nextToken());

}

text.setText(text.getText()+” “+(d1/d2));//将运算结果放到text区域

}

}

3.完整代码见

http://www.cnitstudy.com/f/article/3.html

java swing实现简单的计算器可加减乘除连续计算相关教程

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